Advertisements
Advertisements
Question
The sum of the exponents of the prime factors in the prime factorisation of 196, is
Options
1
2
4
6
Solution
Using the factor tree for prime factorization, we have:
Therefore,
`196 = 2xx2xx7xx7`
`196 = 2^2xx7^2`
The exponents of 2 and 7 are 2 and 2 respectively.
Thus the sum of the exponents is `4`
Hence the correct choice is (c).
APPEARS IN
RELATED QUESTIONS
Define HOE of two positive integers and find the HCF of the following pair of numbers:
56 and 88
Find the largest number which exactly divides 280 and 1245 leaving remainders 4 and 3, respectively.
Find the largest number which divides 438 and 606 leaving remainder 6 in each case.
What is the smallest number that, when divided by 35, 56 and 91 leaves remainders of 7 in each case?
A rectangular courtyard is 18 m 72 cm long and 13 m 20 cm broad. it is to be paved with square tiles of the same size. Find the least possible number of such tiles.
Show that the following numbers are irrational.
If the sum of LCM and HCF of two numbers is 1260 and their LCM is 900 more than their HCF, then the product of two numbers is
Show that the square of any positive integer is either of the form 4q or 4q + 1 for some integer q.
Prove that one of any three consecutive positive integers must be divisible by 3.
For any positive integer n, prove that n3 – n is divisible by 6.