Question

10²⁰ electrons, each having a charge of 1.6 x 10^-19 C, flows in a circuit V is 0.1s. What is the current in ampere?

Answer 1

n = 10²⁰ electrons
e = 1.6 × 10^-19C
t = 0.1s
Charge q = ne
= 10²⁰ × 1.6 × 10^-19
= 16C
Current I = \(\frac{q}{t}=\frac{16}{0.1}=160 \mathrm{~A}\)
∴ Current = 160 A