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प्रश्न
`15x^2-28=x`
उत्तर
Given:
`15x^2-28=x`
⇒` 15x^2-x-28=0`
⇒`15x^2-(21x-20x)-28=0`
`⇒15x^2-21x+20x-28=0`
⇒`3x(5x-7)+4(5x-7)=0`
⇒`(3x+4)(5x-7)=0`
` ⇒3x+4=0 or 5x-7=0`
`⇒ x=(-4)/3 or x=7/5`
Hence, the roots of the equation are `(-4)/3 and 7/5`
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