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प्रश्न
`2x^2+5x-3=0`
उत्तर
`2x^2+5x-3=0`
⇒`4x^2+10x-6=0` (Multiplying both sides by 2)
4x^+10x=6
`(2x)^2+2xx2x xx5/2+(5/2)^2=6+(5/2)^2` [Adding `(5/2)^2`on both sides]
`(2x+5/2)^2=6+25/4=(24+25)/4=49/4=(7/2)^2`
`2x+5/2=7/2` (Taking square root on both sides)
`2x+5/2=7/2 or 2x+5/2=7/2`
`2x=7/2-5/2=2/3=1 or 2x=-7/2-5/2=12/2=-6`
`x=1/2 or x=-3`
Hence, `1/2` and `-3`are the roots of the given equation.
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