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प्रश्न
38 people donated to an organisation working for differently abled persons. The amount in rupees were as follows:
101, 500, 401, 201, 301, 160, 210, 125, 175, 190, 450, 151, 101, 351, 251, 451, 151, 260, 360, 410, 150, 125, 161, 195, 351, 170, 225, 260, 290, 310, 360, 425, 420, 100, 105, 170, 250, 100.
- By taking classes 100-149, 150-199, 200-249... prepare grouped frequency distribution table.
- From the table, find the number of people who donated rupees 350 or more.
उत्तर
Given:
38 people donated to an organisation working for differently abled persons. The amount in rupees were as follows:
101, 500, 401, 201, 301, 160, 210, 125, 175, 190, 450, 151, 101, 351, 251, 451, 151, 260, 360, 410, 150, 125, 161, 195, 351, 170, 225, 260, 290, 310, 360, 425, 420, 100, 105, 170, 250, 100.
(i) The grouped frequency distribution table of the given data is as follows:
| Class interval | Tally marks | Frequency |
| 100 - 149 | `cancel(bb|bb|bb|bb|)` `bb|bb|` | 7 |
| 150 - 199 | `cancel(bb|bb|bb|bb|)` `cancel(bb|bb|bb|bb|)` | 10 |
| 200 - 249 | `bb|bb|bb|` | 3 |
| 250 - 299 | `cancel(bb|bb|bb|bb|)` | 5 |
| 300 - 349 | `bb|bb|` | 2 |
| 350 - 399 | `bb|bb|bb|bb|` | 4 |
| 400 - 449 | `bb|bb|bb|bb|` | 4 |
| 450 - 499 | `bb|bb|` | 2 |
| 500 - 549 | `bb|` | 1 |
| Total | 38 |
(ii) As, 4 + 4 + 2 + 1 = 11
So, the number of people who donated rupees 350 or more is 11.
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संबंधित प्रश्न
Complete the Following Table.
| Classes (age) | Tally marks | Frequency (No. of students) |
| 12-13 | `cancel(bb|bb|bb|bb|)` | `square` |
| 13-14 | `cancel(bb|bb|bb|bb|)` `cancel(bb|bb|bb|bb|)` `bb|bb|bb|bb|` | `square` |
| 14-15 | `square` | `square` |
| 15-16 | `bb|bb|bb|bb|` | `square` |
| N = ∑f = 35 |
Construct a cumulative frequency distribution table from the frequency table given below:
( i )
| Class Interval | Frequency |
| 0 - 8 | 9 |
| 8 - 16 | 13 |
| 16 - 24 | 12 |
| 24 - 32 | 7 |
| 32 - 40 | 15 |
( ii )
| Class Interval | Frequency |
| 1 - 10 | 12 |
| 11 - 20 | 18 |
| 21 - 30 | 23 |
| 31 - 40 | 15 |
| 41 - 50 | 10 |
Observe the given frequency table to answer the following:
| Class Interval | 20 - 24 | 25 29 | 30 - 34 | 35 - 39 | 40 - 44 | 45 - 49 |
| Frequency | 6 | 12 | 10 | 15 | 9 | 2 |
a. The true class limits of the fifth class.
b. The size of the second class.
c. The class boundaries of the fourth class.
d. The upper and lower limits of the sixth class.
e. The class mark of the third class.
Inclusive series is a continuous series
Size of the class 150 – 175 is ______.
Tally marks are used to find ______.
Upper limit of class interval 75 – 85 is ______.
In the class intervals 10 – 20, 20 – 30, etc., respectively, 20 lies in the class ______.
If the fifth class interval is 60 – 65, fourth class interval is 55 – 60, then the first-class interval is 45 – 50.
Following are the number of members in 25 families of a village:
6, 8, 7, 7, 6, 5, 3, 2, 5, 6, 8, 7, 7, 4, 3, 6, 6, 6, 7, 5, 4, 3, 3, 2, 5.
Prepare a frequency distribution table for the data using class intervals 0 – 2, 2 – 4, etc.
