हिंदी

8-digit numbers are formed using the digits 1, 1, 2, 2, 2, 3, 4, 4. The number of such numbers in which the odd digits do no occupy odd places is ______. -

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प्रश्न

8-digit numbers are formed using the digits 1, 1, 2, 2, 2, 3, 4, 4. The number of such numbers in which the odd digits do no occupy odd places is ______.

विकल्प

  • 160

  • 120

  • 60

  • 48

MCQ
रिक्त स्थान भरें

उत्तर

8-digit numbers are formed using the digits 1, 1, 2, 2, 2, 3, 4, 4. The number of such numbers in which the odd digits do no occupy odd places is 120.

Explanation:

In 8 digits numbers, 4 places are odd places.

Also, in the given 8 digits, there are three odd digits 1, 1 and 3.

No. of ways three odd digits arranged at four even places = `(""^4"P"_3)/(2!)` = `(4!)/(2!)`

No. of ways the remaining five digits 2, 2, 2, 4 and 4 arranged at remaining five places = `(5!)/(3!2!)`

Hence, required number of 8 digits number

= `(4!)/(2!) xx (5!)/(3!2!)`

= 120

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