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प्रश्न
A 2-m long thin and straight metal wire carries a positive charge of 3 µ C. (a) What is the linear charge density on the wire? (b) Hence, find the electric intensity at a point 1.5 m away from the centre of the wire.
संख्यात्मक
उत्तर
Data: q = 3 µC = 3 × 10−6 C, l = 2 m, r = 1.5 m, π = 3.142, and ε0 = 8.85 × 10−12 C2/N.m2
Charge density, λ = `q/l`
= `(3 xx 10^-6)/1.5`
= 2 × 10−6 C/m
Electric intensity, E = `λ/(2πε_0r)`
= `(2 xx 10^-6)/(2(3.142)(8.85 xx 10^-12)(1.5))`
= `10^6/(3.142 xx 8.85 xx 1.5)`
log 3.142 0.4972
log 8.85 + 0.9469
log 1.5 + 0.1761
1.6202
log 106 6.0000
− 1.6202
4.3798
antilog 4.3798 = 2.397
= 2.397 × 104 N/C
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Application of Gauss' Law
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