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प्रश्न
a (a2 + a + 1) + 5 and find its values for
- a = 0,
- a = 1,
- a = − 1.
योग
उत्तर
a (a2 + a + 1) + 5a
upon solving this
a × a2 + a × a + a × 1 + 5
= a3 + a2 + a + 5
- Putting a = 0 in the above equation,
a3 + a2 + a + 5
= (0)3 + (0)2 + (0) + 5
= 5 - Putting a = 1 in the above equation,
13 + 12 + (1) + 5
= 1 + 1 + 1 + 5
= 8 - Putting a = −1 in the above equation,
(-1)3 + (-1)2 + (-1) + 5
= − 1 + 1 − 1 + 5
= 4
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