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प्रश्न
A and B together can complete a piece of work in 6 days. A can do it alone in 10 days. Find the number of days in which B alone can do the work.
उत्तर
Let the number of days in which B alone can do the work be x days.
So, B can do `(1)/x` part of the work in a day.
Given that the number of days in which A alone can do the work is 10 days.
So. A can do `(1)/(10)` part of the work in a day.
Together they can complete the work in 6 days.
So, together they can do `(1)/(10)` part of the work in a day.
As per the given condition,
`(1)/x + (1)/(10) = (1)/(6)`
⇒ `(10 + x)/(10x) = (1)/(6)`
⇒ 6(10 + x) = 10x
⇒ 60 + 6x = 10x
⇒ 4x = 60
⇒ x = 15
Hence, B can complete the work in 15days.
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