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प्रश्न
A ball is thrown vertically upward from the ground with an initial velocity of 39.2 m/sec. If the only force considered is that attributed to the acceleration due to gravity, find how high the ball will rise?
उत्तर
Initial velocity of the ball = 39.2 m/sec
Let s be the distance of the ball from the ground at time t.
u = 39.2 m/s.
s = `"ut" - 1/2 * "gt"^2` where g = 9.8 m/sec.
s = `39.2 "t" - 1/2 xx (9.8)"t"^2`
s = 39.2t – 49t2
At maximum height v = 0
⇒ (2)
⇒ – 9.8t + 39.2 = 0
t = 4 sec
⇒ (3)
⇒ x = `- (9.8 xx 16)/2 + 39.2 xx 4`
= – 78.4 + 156.8
= 78.4 m/s
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