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A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, -

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प्रश्न

A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is ______.

विकल्प

  • 6.28 × 10-3 N

  • 0.0314 N

  • 9.859 × 10-2 N

  • 9.859 × 10-4 N

MCQ
रिक्त स्थान भरें

उत्तर

A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is 9.859 × 10-4 N.

Explanation:

Given, m = 200 g, r = 20 cm, T = 40 s

Using the expression

T = `(2pi)/omega`

`omega = (2pi)/40 = pi/20=3.14/20` radian/second

Normal force will provide the necessary centripetal force.

N = mrω= `(200/100)(20/100)[3.14/20]^2`

= 9.859 × 10-4 N.

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