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प्रश्न
A block of mass 200 g moving in x direction with a constant speed of 30 ms-1, is subjected to a retarding force F = 0.1x J/m during its travel from x = 10 m to 20 m. Its final KE will be ____________.
विकल्प
75 J
175 J
50 J
105 J
MCQ
रिक्त स्थान भरें
उत्तर
A block of mass 200 g moving in x direction with a constant speed of 30 ms-1, is subjected to a retarding force F = 0.1x J/m during its travel from x = 10 m to 20 m. Its final KE will be 75 J.
Explanation:
Using Work-Energy Theorem,
`"W" = 1/2"m" ("v"^2 - "u"^2)`
`therefore "Final K.E .,"`
`1/2"mv"^2 = "W" + 1/2"mu"^2`
`= -0.1 int_10^20 "xdx" + 1/2 xx 0.2 xx 30^2 (because "W" = vec"F". vec"s")`
(Negative sign indicates retardation)
`= -0.1 ["x"^2/2]_10^20 + 90`
` = -0.1 [20^2/2 - 10^2/2] + 90`
`= -15 + 90`
`= 75 "J"`
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Work Energy Theorem
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