Advertisements
Advertisements
प्रश्न
A body of mass 100 kg is lifted up by 10 m. Find :
(i) the amount of work done
(ii) potential energy of the body at that height (value of g = 10 m/s2)
उत्तर
(i) Mass of the body, (m) = 100 kg
Height above the ground, (h) = 10 m
Acceleration due to gravity, (g) = 10 m/s2
We can calculate the work done against gravity as,
Work done in lifting a body = (Weight of body) × (Vertical distance)
So, W = (m) × (g) × (h)
So work done,
W = (100) × (10) × (10) J
= 10 KJ
(ii) Potential energy of a body kept at the same height is equal to the amount of work done against gravity in moving the body to that position. Therefore, the potential energy of the body at that height is 10 KJ .
APPEARS IN
संबंधित प्रश्न
A lamp consumes 1000 J of electrical energy in 10 s. What is its power?
What is the work done by the force of gravity on a satellite moving round the earth? Justify your answer.
An electric heater is rated 1500 W. How much energy does it use in 10 hours?
A load of 100 kg is pulled up by 5 m. Calculate the work done. (g = 9.8 m/s2)
Name the physical quantity whose unit is watt.
A trolley is pushed along a road with a force of 400 N through a distance of 60 m in 1 minute. Calculate the power developed.
An electric heater uses 600 kJ of electrical energy in 5 minutes. Calculate its power rating.
A car of weight 20000 N climbs up a hill at a steady speed of 8 m/s, gaining a height of 120 m is 100 s. Calculate : work done by the car.
In an experiment to measure his power, a student records the time taken by him in running up a flight of steps on a staircase. Use the following data to calculate the power of the student :
Number of steps = 28
Height of each step = 20 cm
Time taken = 5.4 s
Mass of student = 55 kg
Acceleration = 9.8 m s−2
due to gravity
An electric motor raises a load of 0.2 kg, at a constant speed, through a vertical distance of 3.0 m in 2 s. If the acceleration of free fall is 10 m/s2, the power in W developed by the motor in raising the load is :