हिंदी

A body of mass 10 kg is attached to a wire 0.3 m long. Its breaking stress is 4.8 × 107 N/m2. The area of cross-section of the wire is 10-6m2. -

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प्रश्न

A body of mass 10 kg is attached to a wire 0.3 m long. Its breaking stress is 4.8 × 10N/m2. The area of cross-section of the wire is 10-6m2. The maximum angular velocity with which it can be rotated 111 a horizontal circle is ______.

विकल्प

  • 6 rad/s

  • 5 rad/s

  • 7 rad/s

  • 4 rad/s

MCQ
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उत्तर

A body of mass 10 kg is attached to a wire 0.3 m long. Its breaking stress is 4.8 × 10N/m2. The area of cross-section of the wire is 10-6m2. The maximum angular velocity with which it can be rotated 111 a horizontal circle is 4 rad/s.

Explanation:

m = 10 kg l = 0.3 m

B.S. = 4.8 × 107 N/m2       A = 10-6m2

∴ F = 4.8 × 107 × 10-6 = 48 N

`"mv"^2/r=48`

`"v"^2=(48xx0.3)/10=144/100`

`"v"=12/10=1.2  "m/s"`

`omega=1.2/r=1.2/0.3=` 4 rad/sec

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Applications of Uniform Circular Motion
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