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प्रश्न
A body of mass 2 kg is acted upon by two forces each of magnitude 1 N and inclined at 60° with each other. The acceleration of the body in m/s is ____________. [cos 60° = 0.5]
विकल्प
`sqrt(0.75)`
`sqrt(0.65)`
`sqrt(0.20)`
`sqrt(0.35)`
MCQ
रिक्त स्थान भरें
उत्तर
A body of mass 2 kg is acted upon by two forces each of magnitude 1 N and inclined at 60° with each other. The acceleration of the body in m/s is `underline(sqrt(0.75))`.
Explanation:
Given, F1 = F2 = 1 N, m = 2 kg and θ = 60°
Resultant force, F = `sqrt("F"_1^2 + "F"_2^2 + 2"F"_1"F"_2 cos θ)`
= `sqrt(1^2 + 1^2 + 2 cos 60°)`
= `sqrt(2 + 2(0.5))`
= `sqrt3` N
ma = `sqrt3`
or a = `sqrt3/"m" = sqrt3/2 = sqrt(3/4) = sqrt0.75 "ms"^-2`
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