Advertisements
Advertisements
प्रश्न
A body of mass m falls from a height h1 to a height h2, above the ground (h1 > h2). What is the loss of potential energy?
उत्तर
At height h1, initial potential energy of body = mgh1
At height h2, final potential energy of body = mgh2
Loss in potential energy = Initial potential energy − Final potential energy
= (mgh1 − mgh2)
= mg (h1 − h2)
APPEARS IN
संबंधित प्रश्न
Differentiate between the potential energy (U) and the kinetic energy (K).
Renewable source of energy is:
Name two examples in which the mechanical energy of a system remains constant.
What happens to the K.E. when
(i) the mass of the body is doubled at a constant velocity and
(ii) the velocity of the body is doubled at constant mass?
State the energy changes which take place in Electricity is obtained from solar energy.
State the energy changes which take place when:
An air gun is loaded and then fired.
Give one example when:
Mechanical energy to heat energy.
A ball of mass 50 g falls from a height of 2m and rebounds from the ground to 1.6 m. Find:
(i) The potential energy possessed by the ball when initially at rest.
(ii) The kinetic energy of the ball before it hits the ground.
(iii) The final potential energy of the ball.
(iv) The loss in kinetic energy of the ball on collision. (Take: g = 10N kg−1)
The major problem in harnessing nuclear energy is how to
Name the type of energy (kinetic energy K or potential energy U) possessed in the following case:
A compressed spring