Advertisements
Advertisements
प्रश्न
A body of volume 100 cm3 weighs 1 kgf in air. Find:
(i) Its weight in water and
(ii) Its relative density.
उत्तर
Volume of body = 100 cm3
Weight in air , W1 = 1 kgf = 1000 gf
Mass of body = 1 kg = 1000 g
R.D. of solid = 10
R.D. of water = 1
(i) Let W2 be the weight of the body in water.
R.D. of body = `W_1/(W_1 - W_2) xx "R.D. of water"`
or , 10 = `1000/((1000 - W_2)) xx 1`
or , 10(1000 - W2) = 1000
or , 1000 - W2 = 100
or , W2 = 900 gf
(ii) R.D. of body = Density in C.G.S. (without unit)
or , R.D. = `"Mass"/"Volume" = 1000/100 = 10`
APPEARS IN
संबंधित प्रश्न
A solid of density 5000 kg m-3 weighs 0.5 kgf in air. It is completely immersed in water of density 1000 kg m-3. Calculate the apparent weight of the solid in water.
How are the (i) Mass, (ii) Volume and (iii) Density of a metallic piece affected, if at all, with an increase in temperature?
What is the unit of relative density?
A piece of stone of mass 15.1 g is first immersed in a liquid and it weighs 10.9 gf. Then on immersing the piece of stone in water, it weighs 9.7 gf. Calculate:
- The weight of the piece of stone in air,
- The volume of the piece of stone,
- The relative density of stone,
- The relative density of the liquid.
A solid weighs 1.5 kgf in air and 0.9 kgf in a liquid of density 1.2 × 103 kg m-3. Calculate R. D. of solid.
A solid of R.D. = 2.5 is found to weigh 0.120 kgf in water. Find the wt. of solid in air.
A solid weighs 105 kgf in air. When completely immersed in water, it displaces 30,000 cm3 of water, calculate relative density of solid.
A body of volume 100 cm3 weighs 1 kgf in air. Calculate its weight in water. What is its relative density?