हिंदी

A body starts from rest on a long inclined plane of slope 45°. The coefficient of friction between the body and the plane varies as µ = 0.3 x, where x is distance travelled down the plane. -

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प्रश्न

A body starts from rest on a long inclined plane of slope 45°. The coefficient of friction between the body and the plane varies as µ = 0.3 x, where x is distance travelled down the plane. The body will have maximum speed (for g = 10 m/s2) when x = ______.

विकल्प

  • 9.8 m

  • 27 m

  • 12 m

  • 3.33 m

MCQ
रिक्त स्थान भरें

उत्तर

A body starts from rest on a long inclined plane of slope 45°. The coefficient of friction between the body and the plane varies as µ = 0.3 x, where x is distance travelled down the plane. The body will have maximum speed (for g = 10 m/s2) when x = 3.33 m.

Explanation:

a = g sin θ - µg cos θ  

a = g sin θ - 0.3 xg cos θ

= `"g"/sqrt2-(0.3"g"x)/sqrt2=5sqrt2-0.3(5sqrt2)x=5sqrt2-1.5sqrt2x`

Velocity will increase until a = 0 and when v = vmax, then a = 0

0 = `5sqrt2-1.5sqrt2x`

x = `(5sqrt2)/(1.5sqrt2)`

x = 3.33 m

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Friction
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