Advertisements
Advertisements
प्रश्न
A body travels a distance of 3 km towards East, then 4 km towards North and finally 9 km towards East.
What is the resultant displacement ?
उत्तर
The body travels a total distance of 12 km east, which means towards the x-axis, on a Cartesian plane. It travels a distance of 4 km in north direction, which means towards y-axis.
Resultant displacement :
`sqrt(12^2+4^2)`
= `sqrt(144 + 16)`
= `sqrt(160)`
= 12.65 km
APPEARS IN
संबंधित प्रश्न
A particle is moving in a circular path of radius r. The displacement after half a circle would be :
Draw a velocity-time graph for a body moving with an initial velocity u and uniform acceleration a. Use this graph to find the distance travelled by the body in time t.
Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.
Compare the distance travelled in part BC with the distance travelled in part AB.
A car starting from rest accelerates uniformly to acquire a speed 20 km h-1 in 30 min. The distance travelled by a car in this time interval will be _____________
A body starts with an initial velocity of 10m s-1 and acceleration 5 m s-2. Find the distance covered by it in 5 s.
Define Displacement.
Calculate the distance and displacement in the following case:
Exercise Problems.
An athlete completes one round of a circular track of diameter 200 m in 40 s. What will be the distance covered and the displacement at the end of 2 m and 20 s?
Which of the following is correct?
Write a note on the following:
knot
