Advertisements
Advertisements
प्रश्न
A body weighs 300 gf in air and 280 gf when completely immersed in water. Calculate:
(i) The loss in weight of the body,
(ii) The upthrust on the body.
उत्तर
Weight of the body in air = 300 gf.
Apparent Weight of the completely immersed body in water = 280 gf.
(i) Loss in weight of the body = Weight of body in air - apparent weight of the immersed body.
Loss in weight = 300 gf - -280 gf = 20 gf.
(ii) As upthrust on the body = loss in weight
(iii) So uptrust = 20 gf.
APPEARS IN
संबंधित प्रश्न
A body of density ρ sinks in a liquid of density ρL. The densities ρ and ρL are related as :
Express the relationship between the C.G.S. and S.I. units of density.
A body floats in a liquid with a part of it submerged inside the liquid. Is the weight of floating body greater than, equal to or less than the upthrust?
A man first swims in sea water and then in river water. (i) Compare the weights of sea water and river water displaced by him.
(ii) Where does he find it easier to swim and why?
A body of mass ‘m’ is floating in a liquid of density ‘p’
what is the apparent weight of body?
A body of mass ‘m’ is floating in a liquid of density ‘p’
what is the loss of weight of body?
A solid body weighs 2.10 N. in air. Its relative density is 8.4. How much will the body weigh if placed
(1) in water,
(2) in liquid of relative density 1.2?
Select the correct option:
With the increase in the density of the fluid, the upthrust experienced by a body immersed in it:
Complete the following result:
Mass = _______ × density