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A Body Weighs W1gf in Air and When Immersed in a Liquid It Weighs W2gf, While It Weights W3gf on Immersing It in Water. Find: (I) Volume of the Body (Ii) Upthrust Due to Liquid (Iii) Relative Den - Physics

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प्रश्न

A body weighs W1gf in air and when immersed in a liquid it weighs W2gf, while it weights W3gf on immersing it in water. Find: (i) volume of the body (ii) upthrust due to liquid (iii) relative density of the solid and (iv) relative density of the liquid.

संक्षेप में उत्तर

उत्तर

(i) Volume of the body = W- Wcm3

(ii) Upthrust due to liquid = loss in weight when immersed in liquid = W1 - Wgf

(iii)

Weight of a body in air = W1gf

Weight of that body in liquid = W2gf

Weight of that body in water = W3gf 

RD of solid = `"Weight of solid in air"/"Weight in air - Weight in water"`

= `"W"_1/("W"_1 - "W"_3)`

(iv)

Weight of a body in air = W1gf

Weight of that body in liquid = W2gf

Weight of that body in water = W3gf 

RD of Liquid = `(W_1 - W_2)/(W_1 - W_3)`

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Determination of Relative Density of a Solid Substance by Archimedes’ Principle
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Upthrust in Fluids, Archimedes’ Principle and Floatation - Exercise 5 (B) [पृष्ठ ११६]

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सेलिना Concise Physics [English] Class 9 ICSE
अध्याय 5 Upthrust in Fluids, Archimedes’ Principle and Floatation
Exercise 5 (B) | Q 15 | पृष्ठ ११६

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