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A Bought a Cycle and Spent Rs.110 on Its Repair. He Then Sold It to B at 20% Profit. B Sold It to C at 10% Loss. C Sold It for Rs.1188 at 10% Profit. How Much Did a Pay for the Article? - Mathematics

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प्रश्न

A bought a cycle and spent Rs.110 on its repair. He then sold it to B at 20% profit. B sold it to C at 10% loss. C sold it for Rs.1188 at 10% profit. How much did A pay for the article?

योग

उत्तर

Let A buy the cycle for Rs. x.
For A, C.P. of the cycle = Rs. x + Rs. 110
Profit = 20%
`"S.P."/"C.P." = 1 + "Profit"/(100)`

⇒ `"S.P."/(x + 110) = 1 + (20)/(100)`

⇒ `"S.P."/(x + 110) = (100 + 20)/(100)`

⇒  S.P. = `(120)/(100) (x + 100)`

= Rs.`(12)/(10)(x + 110)`

For B, C.P. of the cycle = Rs.`(12)/(10)(x + 110)`
Loss = 10%
`"S.P."/"C.P." = 1 - "Loss"/(100)`

⇒ `"S.P."/(12/10(x + 110)) = 1 - (10)/(100)`

⇒ `"S.P."/(12/10(x + 110)) = (100 - 10)/(100)`

⇒ S.P. = `(90)/(100) (12)/(10) (x + 110)`

= Rs. `(9)/(10).(12)/(10)(x + 110)`

For C, C.P. of the cycle
= Rs. `(9)/(10).(12)/(10)(x + 110)`
Profit = 10%
S.P. of the cycle
= Rs.`(1 + 10/100) (9)/(10).(12)/(10)(x + 110)`

= Rs. `(11)/(10).(9)/(10).(12)/(10)(x + 110)`

ATQ, `(11)/(10).(9)/(10).(12)/(10)(x + 110)`
= 1188
⇒  x + 110 = 1000
⇒  x = 1000 - 110
= 890
∴ A paid Rs.890 for the cycle.

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To Find C.P., When S.P. and Gain (Or Loss) Percent Are Given
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Profit , Loss and Discount - Exercise 2.2

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फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 2 Profit , Loss and Discount
Exercise 2.2 | Q 22

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