Question

A capacitor C₁ = 4µF is connected is series with another capacitor C₂ = 1µF. The combination is connected across d.c. source of 200 V. The ratio of potential across C₂ to that across C₁ is ______.

विकल्प

• 16 : 1

• 8 : 1

• 2 : 1

• 4 : 1

Answer 1

A capacitor C₁ = 4µF is connected is series with another capacitor C₂ = 1µF. The combination is connected across d.c. source of 200 V. The ratio of potential across C₂ to that across C₁ is 4 : 1.

Explanation:

C₁ = 4µF

C₂ = 1µF

`"C"_"eq"=("C"_1xx"C"_2)/("C"_1+"C"_2)=(4xx1)/(4+1)=0.8  mu"F"`

Q = C_eqV = 0.8µF × 200 V =160µC

`therefore"V"_1="Q"/"C"_1=(160mu"C")/(4mu"C")=40`

`"V"_2="Q"/"C"_2=(160mu"C")/(1mu"C")=160`

V₂ : V₁ = 4 : 1