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A charge of 8860 C flows through an electric circuit in 2 min and 40 s. Calculate the magnitude of current in circuit. - Physics

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प्रश्न

A charge of 8860 C flows through an electric circuit in 2 min and 40 s. Calculate the magnitude of current in a circuit.

योग

उत्तर

Charge = Q = 8860 C

Time = t = 2 min 40 s

t = (2 × 60 + 40)s

t = 160 s

Electric current = I = ?

I = `"Q"/"t" = 8860/160`

I = 55.375 A

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Types of Circuits: Simple Circuit
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अध्याय 10: Electricity and Magnetism – 1 - Unit I Practice Problems 1

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गोयल ब्रदर्स प्रकाशन A New Approach to ICSE Physics Part 1 [English] Class 9
अध्याय 10 Electricity and Magnetism – 1
Unit I Practice Problems 1 | Q 2
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