Advertisements
Advertisements
प्रश्न
A cube of mass 'M' and side 'L' is fixed on the horizontal surface. The modulus of rigidity of the material of the cube is 'η'. A force is applied perpendicular to one of the side faces. When the force is removed, the cube executes small oscillations. The time period ______
विकल्प
`2pisqrt(M/(ηL))`
`2pisqrt(η/(ML))`
`M/(2pietaL)`
`(2pietaL)/M`
उत्तर
A cube of mass 'M' and side 'L' is fixed on the horizontal surface. The modulus of rigidity of the material of the cube is 'η'. A force is applied perpendicular to one of the side faces. When the force is removed, the cube executes small oscillations. The time period `underline(2pisqrt(M/(ηL)))`.
Explanation:
`eta = F/L^2 . L/(DeltaL)`
= `F/(LDeltaL)`
∴ F = ηLΔL
F = kΔL where k = ηL
∴ `T = 2pisqrt(M/k) = 2pisqrt(M/(etaL))`