Question

A cuboidal container having dimensions 2 m × 1.5 m × 0.5 m holds a mixture of 12 g of He, 36 g of Ar, and 20 g of Ne, If the container is maintained at 300 K, Find the pressure exerted by the mixture (given M_He = 4, M_Ar = 40, M_Ne = 20). 

विकल्प

• 4055.2 N/m²

• 814.38 N/m²

• 8143.8 N/m²

• 405.5 N/m²

Answer 1

8143.8 N/m²

Explanation:

We apply Dalton's law of partial pressures to a mixture of inert gases.

∴ P = P_He + P_Ar + P_Ne

= `"RT"/"V" ["m"_"He"/"M"_"He" + "m"_"Ar"/"M"_"Ar" + "m"_"Ne"/"M"_"Ne"]`

= `(8.31 xx 300)/((2 xx 1.5 xx 0.5)) [12/4 + 36/40 + 20/20]`

= 1662 × (3 + 0.9 + 1)

∴ P = 8143.8 N/m²