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A cylindrical roller 2.5 m in length, 1.75 m in radius when rolled on a road was found to cover the area of 5500 m2. How many revolutions did it make? - Mathematics

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प्रश्न

A cylindrical roller 2.5 m in length, 1.75 m in radius when rolled on a road was found to cover the area of 5500 m2. How many revolutions did it make?

योग

उत्तर

Given: length of cylindrical roller, i.e., height of the cylinder, h = 2.5 m

Radius of cylindrical roller, r = 1.75 m

The cylindrical roller will roll on the road only from its curved surface.

So, curved surface area of cylindrical roller, CSA = 2πrh

⇒ CSA = 2 × `22/7` × 1.75 × 2.5 = 27.5 m2

⇒ Area of road covered in 1 revolution = 27.5 m2

And given that, total area of road covered = 5500 m2

So, number of revolutions made by road roller to cover 5500 m2 = `5500/27.5` = 200

 Thus, it made 200 revolutions.

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अध्याय 13: Surface Area & Volumes - Exercise 13.3 [पृष्ठ १२७]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 9
अध्याय 13 Surface Area & Volumes
Exercise 13.3 | Q 7. | पृष्ठ १२७

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