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प्रश्न
A flywheel of mass 20 kg and radius 5 cm is revolving at a speed of 300 rpm. Its kinetic energy is ______.
विकल्प
`25/pi` J
2.5`pi^2` J
3.6`pi^2` J
1.6 `pi^2` J
MCQ
रिक्त स्थान भरें
उत्तर
A flywheel of mass 20 kg and radius 5 cm is revolving at a speed of 300 rpm. Its kinetic energy is 2.5 `pi^2` J.
Explanation:
M = 20kg
R = 5 cm= 0.05 m
n = 300 rpm=`300/60` = 5 rps
∴ I= MR2 = (20) x (0.05)2 = 0.05 kg m2
∴ E = `1/2 "I"omega^2`
= `1/2 "I" (2pi"n")^2`
= `2pi^2 "In"^2`
= `2pi^2 xx (0.05) xx 25 = 2.5pi^2 ` J
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