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प्रश्न
उत्तर
We know that,
P=VI
I = `"P"/"V" = (5 xx 1000)/200` = 25A
Thus, safe limit of current through t he appliance is 25A and a fuse of rating BA cannot be used with an appliance of rating SkW, 200 v.
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संबंधित प्रश्न
Draw the electrical symbols of the following components and state its use:
Ammeter.
A student made an electric circuit shown here to measure the current through two lamps.
Are the lamps in series or parallel?
(a) Are the lamps in series or parallel?
(b) The student has made a mistake in this circuit. What is the mistake?
(c) Draw a circuit diagram to show the correct way to connect the circuit. Use the proper circuit symbols in your diagram.
An electric bulb of resistance 20 Ω and a resistance wire of 4 Ω are connected in series with a 6 V battery.
Draw the circuit diagram, and calculate:
(a) total resistance of the circuit.
(b) current through the circuit.
(c) potential difference across the electric bulb.
(d) potential difference across the resistance wire.
If the lamps are both the same in the figure given below and if A1 reads 0.50 A, what do A2, A3, A4 and A5 read?
Find the effective resistance in the following circuit diagrams (Fig.):
An auto lamp is joined to a battery of e.m.f. 4 V and internal resistance 2.5Ω. A steady current of 0.5 A flows through the circuit. Calculate the
(a) Total energy provided by battery in 10 minutes,
(b) Heat dissipated in the bulb in 10 minutes.
1 kWh = `(1 "volt" xx 1 "ampere" xx "_________")/1000`
State the condition when it is advantageous to connect cells in parallel.
