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A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 and these are equally likely outcomes. - Mathematics

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प्रश्न

A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see the given figure), and these are equally likely outcomes. What is the probability that it will point at

  1. 8?
  2. an odd number?
  3. a number greater than 2?
  4. a number less than 9?

योग

उत्तर

(1) Total number of possible outcomes = 8

The number of favourable outcome = 1

Probability of getting 8 =  `"Number of favourable outcomes"/"total number of outcomes"`

= `1/8`

(2) Total number of odd numbers on spinner = 4

Probability of getting an Odd Number =  `"Number of favourable outcomes"/"total number of outcomes"`

= `4/8 `

= `1/2`

(3) The numbers greater than 2 are 3, 4, 5, 6, 7, and 8.

Therefore, total numbers greater than 2 = 6

Probability of getting a Number greater than 2 = `"Number of favourable outcomes"/"total number of outcomes"`

= `6/8`

= `3/4`

(4) The numbers less than 9 are 1, 2, 3, 4, 6, 7, and 8.

Therefore, total numbers less than 9 = 8

Probability of getting a number less than 9

=  `8/8`

= 1 

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अध्याय 15: Probability - Exercise 15.1 [पृष्ठ ३०९]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 10
अध्याय 15 Probability
Exercise 15.1 | Q 12 | पृष्ठ ३०९

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