Advertisements
Advertisements
प्रश्न
A girl walks along a straight path to drop a letter in the letterbox and comes back to her initial position. Her displacement–time graph is shown in Fig.8.4. Plot a velocity-time graph for the same.
उत्तर
From displacement – time graph,
velocity = `"displacement"/"time"`
= `(100"m")/(50"s")`
= 2ms−1
The symmetry of the graph shows that the girl comes back to her initial position with the same velocity (2 ms−1) but in opposite direction. So, the velocity-time graph will look like
APPEARS IN
संबंधित प्रश्न
Which of the two can be zero under certain conditions : average speed of a moving body or average velocity of a moving body ?
Explain why, the motion of a body which is moving with constant speed in a circular path is said to be accelerated.
A bus running at a speed of 18 km/h is stopped in 2.5 seconds by applying brakes. Calculate the retardation produced.
A freely falling object travels 4.9 m in 1st second, 14.7 m in 2 nd second, 24.5 m in 3rd second, and so on. This data shows that the motion of a freely falling object is a case of :
When a car driver travelling at a speed of 10 m/s applies brakes and brings the car to rest in 20 s, then retardation will be :
The velocity-time graph of a body in motion is a straight line inclined to the time axis. The correct statement is ___________
Multiple choice Question. Select the correct option.
A body dropped from the top of a tower reaches the ground in 4s. Height of the tower is
Can you suggest a real-life example about the motion of a body from the following velocity – time graph?
A body is thrown vertically upward with velocity u, the greatest height h to which it will rise is,
An object starting from rest travels 20 m in the first 2 s and 160 m in the next 4 s. What will be the velocity after 7 s from the start?
