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प्रश्न
A grouped frequency table with class intervals of equal sizes using 250 – 270 (270 not included in this interval) as one of the class interval is constructed for the following data:
268, 220, 368, 258, 242, 310, 272, 342, 310, 290, 300, 320, 319, 304, 402, 318, 406, 292, 354, 278, 210, 240, 330, 316, 406, 215, 258, 236.
The frequency of the class 310 – 330 is:
विकल्प
4
5
6
7
उत्तर
6
Explanation:
Here, the lowest value of observation = 210 and the highest value of observation = 406.
So, class intervals are 210 – 230, 230 – 250, ...., 390 – 410.
The required frequency distribution table is
| Class interval | Tally marks | Frequency |
| 210 – 230 | ||| | 3 |
| 230 – 250 | ||| | 3 |
| 250 – 270 | ||| | 3 |
| 270 – 290 | || | 2 |
| 290 – 310 | |||| | 4 |
| 310 – 330 | `cancel(||||)|` | 6 |
| 330 – 350 | || | 2 |
| 350 – 370 | || | 2 |
| 370 – 390 | — | 0 |
| 390 – 410 | ||| | 3 |
Hence, the frequency of the class 310 – 330 is 6.
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