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प्रश्न
A hydride of 2nd period alkali metal (A) on reaction with a compound of Boron (B) to give a reducing agent (C). identify A, B and C.
उत्तर
A hydride of 2nd period alkali metal (A) is lithium hydride (LiH).
Lithium hydride (A) reacts with diborane (B) to give lithium borohydride (C) which is acts as a reducing agent.
\[\ce{\underset{\text{[Diborane (B)]}}{B2H6} + \underset{\text{[Lithium hydride (A)]}}{2LiH} ->[Ether] \underset{\text{[Lithium borohydride (C)]}}{2LiBH4}}\]
(A) Lithium hydride – LiH
(B) Diborane – B2H6
(C) Lithium borohydride – LiBH4
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संबंधित प्रश्न
An aqueous solution of borax is ____________.
Which among the following is not a borane?
Match items in Column – I with the items of Column – II and assign the correct code.
| Column – I | Column – II |
| A. Borazole | 1. B(OH)3 |
| B. Boric acid | 2. B3N3H6 |
| C. Quartz | 3. Na2[B4O5(OH)4]8H2O |
| D. Borax | 4. SiO2 |
The compound that is used in nuclear reactors as protective shields and control rods is ____________.
Write a short note on hydroboration.
Give one example for the following.
Icosogens
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\[\ce{Na2B4O7 + H2SO4 + H2O ->}\]
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\[\ce{B2H6 +CH3OH ->}\]
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\[\ce{BF3 + 9H2O ->}\]
Complete the following reaction.
\[\ce{B + NaOH ->}\]
