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A Lever of Length 100 Cm Has the Effort of 15 Kgf at a Distance of 40 Cm from the Fulcrum at One End. What Load Can Be Applied at Its Other End? - Physics

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प्रश्न

A lever of length 100 cm has the effort of 15 kgf at a distance of 40 cm from the fulcrum at one end. What load can be applied at its other end?

संख्यात्मक

उत्तर

Given,

Effort = 15 kgf

Load arm = 100 cm

Effort arm = 40 cm

Mechanical advantage = `"Effort arm "/"Load arm" = 40 /100 = 0.4`

By definition , 

Mechanical advantage =`"Load"/"Effort"`

∴ 0.4 = `"Load"/"15 kgf"`

⇒ Load = 15 kgf × 0.4

∴  Load = 6 kgf

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अध्याय 4: Simple Machines - Numericals

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सेलिना Concise Physics [English] Class 6 ICSE
अध्याय 4 Simple Machines
Numericals | Q 4
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