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प्रश्न
A linearly polarized electromagnetic wave given as E = Eoî cos (kz – ωt) is incident normally on a perfectly reflecting infinite wall at z = a. Assuming that the material of the wall is optically inactive, the reflected wave will be given as ______.
विकल्प
Er = `- E_ohati cos (kz - ωt)`
Er = `E_ohati cos (kz + ωt)`
Er = `- E_ohati cos (kz + ωt)`
Er = `E_ohati cos (kz - ωt)`
उत्तर
A linearly polarized electromagnetic wave given as E = `E_ohati cos (kz - ωt)` is incident normally on a perfectly reflecting infinite wall at z = a. Assuming that the material of the wall is optically inactive, the reflected wave will be given as `underline(E_r = E_ohati cos (kz + ωt))`.
Explanation:
When a wave is reflected from a denser medium or perfectly reflecting wall made with optically inactive material, then the type of wave doesn’t change but only its phase changes by 180° or π radian.
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