Question

A metal wire of length L, area of cross section A and Young's modulus Y behaves as a spring of spring constant k given by:

विकल्प

• k = `"YA"/"L"`

• k = `(2"YA")/"L"`

• k = `"YA"/(2"L")`

• k = `"YL"/"A"`

Answer 1

`bb("k" = "YA"/"L")`

Explanation:

Y = `("F"/"A")/(lambda/"L")`

= `"FL"/("A"lambda)` on comparing

⇒ F = `"YA"/"L"`λ

⇒ F = k λ       Here,`("k" = "YA"/"L")`