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प्रश्न
A molecule consists of two atoms each of mass 'm' and separated by a distance 'd'. At room temperature the average rotational kinetic energy is 'E', then its angular frequency is ______.
विकल्प
`2/"d" sqrt("E"/"m")`
`sqrt("m"/"Ed")`
`"d"/2 sqrt("m"/"E")`
`sqrt("Ed"/"m"`
MCQ
रिक्त स्थान भरें
उत्तर
A molecule consists of two atoms each of mass 'm' and separated by a distance 'd'. At room temperature the average rotational kinetic energy is 'E', then its angular frequency is `underline(2/"d" sqrt("E"/"m")`.
Explanation:
MI of molecule = `"m"("d"/2)^2 + "m"("d"/2)^2`
`="md"^2/2`
Now, `1/2 "I"omega^2` = E
`omega = sqrt((2"E")/"I") = sqrt((2 xx "E" xx 2)/"md"^2)`
`= 2/"d" sqrt("E"/"m")`
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