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A particle of mass 'm' is moving in time 't' on a trajectory given by r→ =10αt2i^+5β(t-5)j^ Where α and β are dimensional constants. The angular momentum of the particle becomes the same -

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प्रश्न

A particle of mass 'm' is moving in time 't' on a trajectory given by

`vecr  = 10alphat^2hati + 5beta(t - 5)hatj`

Where α and β are dimensional constants.

The angular momentum of the particle becomes the same as it was for t = 0 at time t = ______ seconds.

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MCQ
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उत्तर

A particle of mass 'm' is moving in time 't' on a trajectory given by

`vecr  = 10alphat^2hati + 5beta(t - 5)hatj`

Where α and β are dimensional constants.

The angular momentum of the particle becomes the same as it was for t = 0 at time t = 10 seconds.

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