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प्रश्न
A particle undergoing simple harmonic motion has time dependent displacement given by x(t) = A sin`(pit)/90`. The ratio of kinetic to the potential energy of this particle at t = 210s will be ______.
विकल्प
`1/9`
1
2
`1/3`
MCQ
रिक्त स्थान भरें
उत्तर
A particle undergoing simple harmonic motion has time-dependent displacement given by x(t) = A sin`(pit)/90`. The ratio of kinetic to the potential energy of this particle at t = 210s will be `underlinebb(1/3).`
Explanation:
Kinetic energy, k = `1/2momega^2A^2cos^2omegat`
Potential energy, U = `1/2momega^2A^2sin^2omegat`
`k/U = cot^2omegat = cot^2 pi/90(210) = 1/3`
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Energy in Simple Harmonic Motion
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