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प्रश्न
A person moved from A to B on a circular path as shown in figure. If the distance travelled by him is 60 m, then the magnitude of displacement would be: (Given cos135° = - 0.7)
विकल्प
42 m
47 m
19 m
40 m
MCQ
उत्तर
47 m
Explanation:
From ΔAOB
`"AB"/(sin135)="OB"/(sin 22.5)`
AB = `sin 135/sin22.5"OB"`
= `(sin(135))/(sin(22.5)) ("arc"("AB"))/((3pi)/4)`
= `(sin(45))/(sin(22.5))xx(60xx4)/(3pi)`
= 47 m
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