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प्रश्न
A physical quantity of the dimensions of length that can be formed out of c, G and `e^2/(4piε_0)` is (c is velocity of light, G is universal constant of gravitation and e is charge):
विकल्प
`1/c^2 [G e^2/(4piε_0)]^(1/2)`
`c^2 [G e^2/(4piε_0)]^(1/2)`
`1/c^2 [e^2/(G4piε_0)]^(1/2)`
`1/c G e^2/(4piε_0)`
उत्तर
`1/c^2 [G e^2/(4piε_0)]^(1/2)`
Explanation:
Let the physical quantity formed of the dimensions of length be given as,
[L] = `[c]^x [G]^y [e^2/(4piε_0)]^z` ......(i)
Now,
Dimensions of velocity of light `[c]^x = [LT^-1]^x`
Dimensions of universal gravitational constant `[G]^y = [M^-1L^3T^-2]^y`
Dimensions of `[e^2/(4piε_0)]^z` = [ML3T–2]z
Substituting these in equation (i)
[L] = [LT–1]x [M–1L3T–2]y [ML3T–2]z
= `[L^(x + 3y + 3z) M^(-y + z) T^(-x - 2y - 2z)]`
Solving for x, y, z
x + 3y + 3z = 1
– y + z = 0
x + 2y + 2z = 0
Solving the above equations,
x = – 2, y = `1/2`, z = `1/2`
∴ L = `1/c^2 [G e^2/(4piε_0)]^(1/2)`