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प्रश्न
A plane wavefront is an incident on a water surface at an angle of incidence 60° then it gets refracted at 45°. The ratio of the width of incident wavefront to that of refracted wavefront will be ______
`[sin pi/4 = cos pi/4 = 1/sqrt2, sin60^circ = sqrt3/2, cos60^circ = 1/2]`
विकल्प
`sqrt3/2`
`1/sqrt2`
`sqrt2`
`2sqrt3`
MCQ
रिक्त स्थान भरें
उत्तर
A plane wavefront is an incident on a water surface at an angle of incidence 60° then it gets refracted at 45°. The ratio of the width of incident wavefront to that of refracted wavefront will be `underline(1/sqrt2)`.
Explanation:
`W_1/W_2 = cosi/cosr = cos60^circ/cos45^circ = (1/2)/(1/sqrt2) = sqrt2/2 = 1/sqrt2`
shaalaa.com
Huygens’ Theory
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