Question

A progressive wave of frequency 500 Hz is travelling with a velocity of 360 m/s. How far apart are two points 60° out of phase?

विकल्प

• 0.05 m

• 0.10 m

• 0.12 m

• 0.72 m

Answer 1

0.12 m

Explanation:

Given, v = 360 ms^-1, ν = 500 Hz

ΔΦ = 60° = `pi/3`

Since, the velocity of a wave, v = νλ

⇒ `lambda = "v"/ν = 360/500 = 0.72` m

As, phase difference, ΔΦ = `(2pi)/lambda xx "path difference"(Deltax)`

⇒ `Deltax = lambda/(2pi) xx DeltaPhi = 0.72/(2pi) xx pi/3 = 0.12` m