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प्रश्न
A random variable X bas the following probability distribution:
X = x | 0 | 1 | 2 | 3 |
P(X = x) | 2a | 3a | 4a | a |
The value of P (X > 0) is
विकल्प
0.9
0.6
0.8
0.7
MCQ
उत्तर
0.8
Explanation:
Since `sum_(x= 0)^3`P(X = x) = 1,
2a + 3a + 4a + a = 1
⇒ 10 a = 1
⇒ a = `1/10`
Now, P(X > 0)
= P(X = 1) + P(X = 2) + P(X = 3)
= 3a + 4a + a
= 8a = `8 (1/10) = 0.8`
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