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प्रश्न
A ray of light passes from vacuum into a medium of refractive index µ, the angle of incidence is found to be twice the angle of refraction. Then the angle of incidence is ______.
विकल्प
`2cos^-1(mu/2)`
sin-1(μ)
`sin^-1(mu/2)`
`cos^-1(mu/2)`
MCQ
रिक्त स्थान भरें
उत्तर
A ray of light passes from vacuum into a medium of refractive index µ, the angle of incidence is found to be twice the angle of refraction. Then the angle of incidence is `underlinebb(2cos^-1(mu/2))`.
Explanation:
µ = `sin"i"/sin"r"` ∵ i = 2r
⇒ µ = `(sin2"r")/sin"r"=(2sin"r".cos"r")/sin"r"`
r = `cos^-1(mu/2)`,
∴ i = `2cos^-1(mu/2)`
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