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प्रश्न
A resistance of 5 `Omega` is connected in the left gap of a metre bridge and 15 `Omega` in the other gap. The position of the balancing point is ____________.
विकल्प
10 cm
20 cm
25 cm
75 cm
MCQ
रिक्त स्थान भरें
उत्तर
A resistance of 5 `Omega` is connected in the left gap of a metre bridge and 15 `Omega` in the other gap. The position of the balancing point is 25 cm.
Explanation:
`l/(100 - l) = 5/15 = 1/3`
`3l = 100 - "x"`
`therefore 4l = 100`
`therefore l = 25 "cm"`
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