Advertisements
Advertisements
प्रश्न
A rocket drawing has the measures as given in the figure. Find its area
उत्तर
Area = Area of a rectangle + Area of a triangle + Area of a trapezium
For rectangle length l = 120 – 20 – 20 cm = 80 cm
Breadth b = 30 cm
For the triangle base = 30 cm
Height = 20 cm
For the trapezium height h = 20 cm
Parallel sided a = 50 cm
b = 30 cm
∴ Area of the figure = `("l" xx "b") + (1/2 xx "base" xx "height") + 1/2 xx "h" xx ("a" + "b") "sq.units"`
= `(80 xx 30) + (1/2 xx 30 xx 20) + 1/2 xx 20 xx (50 + 30) "cm"^2`
= 2400 + 300 + 800 cm2
= 3500 cm2
Area of the figure = 3500 cm2
APPEARS IN
संबंधित प्रश्न
Find the area of the shaded part in the following figure. (π = 3.14)
Find the area of the combined figure given, formed by joining a semicircle of diameter 6 cm with a triangle of base 6 cm and height 9 cm. (π = 3.14)
The doormat which is in a hexagonal shape has the following measures as given in the figure. Find its area.
Find the area of the irregular polygon shaped fields given below.
Find the perimeter and area of the following shape
Find the perimeter and area of the following shape
Find the perimeter and area of the following shape
A square of side 2 cm is joined with a rectangle of length 15 cm and breadth 10 cm. Find the perimeter of the combined shape
Two plots have the same perimeter. One is a square of side 10 m and another is a rectangle of breadth 8 m. Which plot has the greater area and by how much?
Look at the picture of the house given and find the total area of the shaded portion.