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A saturated solution, prepared by dissolving CaF2(s) in water, has [Ca2+] = 3.3 × 10−4 M What is the Ksp of CaF2? - Chemistry

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प्रश्न

A saturated solution, prepared by dissolving CaF2(s) in water, has [Ca2+] = 3.3 × 10−4 M What is the Ksp of CaF2?

संख्यात्मक

उत्तर

\[\ce{CaF2_{(s)} ⇌ Ca^{2+}_{( aq)} + 2F^-_{( aq)}}\]

[F] = 2 [Ca2+]

= 2 × 3.3 × 10−4 M

= 6.6 × 10−4 M

Ksp = [Ca2+] [F]2

= (3.3 × 10−4) (6.6 × 10−4)2

= 1.44 × 10−4

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अध्याय 8: Ionic Equilibrium - Evaluation [पृष्ठ ३१]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 8 Ionic Equilibrium
Evaluation | Q 21. | पृष्ठ ३१
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