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A small amount of copper oxide was taken in a beaker and dilute hydrochloric acid was added with continuous stirring of the solution. Name the compound formed and state the colour of its solution. - Science

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प्रश्न

A small amount of copper oxide was taken in a beaker and dilute hydrochloric acid was added with continuous stirring of the solution. Name the compound formed and state the colour of its solution. Write the balanced chemical equation for the reaction that occurs. Based on the reaction, state the nature (acidic/basic) of copper oxide.

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उत्तर

The compound formed when copper oxide reacts with dilute hydrochloric acid is copper(II) chloride (CuCl₂). The solution of copper(II) chloride is typically a blue-green colour.

The balanced chemical equation for the reaction is:

 \[\ce{CuO(s) + 2HCl(aq)−>CuCl2(aq) + H2O(l)}\]

This reaction is a neutralization reaction, where the base (copper oxide) reacts with an acid (hydrochloric acid) to produce a salt (copper(II) chloride) and water.

Based on this reaction, copper oxide is basic in nature because it reacts with an acid to form salt and water.

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