Question

A sniper fires a rifle bullet into a gasoline tank making a hole 53.0 m below the surface of gasoline. The tank was sealed at 3.10 atm. The stored gasoline has a density of 660 kgm⁻³. The velocity with which gasoline begins to shoot out of the hole is (Take g = 10 m/s²). 

विकल्प

• 9.6 ms⁻¹

• 19.7 ms⁻¹

• 27.8 ms⁻¹

• 41.0 ms⁻¹

Answer 1

41.0 ms⁻¹ 

Explanation:

According to Bernoulli's theorem,

`"PB" + "h"ρ"g" = "PA" + 1/2ρ"V"_"A"^2` ......(∵V_A >> V_B)

∴ 3.10P + 53 × 660 × 10 = `"P" + 1/2 xx 660  "V"_"A"^2`

∴ 2.1 × 1.01 × 10⁵ + 3.498 × 10⁵ = `1/2 xx 660 xx "V"_"A"^2`

∴ 5.619 × 10⁵ = `1/2 xx 660 xx "V"_"A"^2`

∴ V_A = `sqrt((2 xx 5.619 xx 10^5)/660) ≈ 41 "m"//"s"`